A small body is placed on the top of a smooth sphere of radius R. Then the sphere is imparted a constant acceleration `w_0` in the horizontal direction and the body begins sliding down. Find:
(a) the velocity of the body relative to the sphere at the moment of break-off,
(b) the angle `theta_0` between the vertical and the radius vector drawn from the centre of the sphere to the break-off point, calculate `theta_0` for `w_0=g`.

Answer

`v=sqrt(2gR//23), cos theta_(0) = (2+nsqrt(5+9n^(2)))/(3(1+n^(2))), theta_(0)=17^(@)`