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Two particles A and B move anticlockwise...

Two particles A and B move anticlockwise with the same speed v in a circle of radius R and are diametrically opposite to each other. At `t=0`, A is given a constant accelerartion (tangential) `a_(t)=(72v^(2))/(25 pi R)`. Calculate the time in which a collides with B, the angle traced by A, its angular velocity and radial acceleration at the time of collision.

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The correct Answer is:
`t=5pi R//6V, theta = 11 pi//6, a_(t)=289 V^(2)//25 R^(3)`
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