Find the phase different between two particles executing simple harmonic motion with the same amplitude and frequency when their phases at a certain moment are as shown in the figure.

The velocity of a particle executing simple harmonic motion is

While a particle executes linear simple harmonic motion

Find the phase difference between two particles executing simple harmonic motion with the same frequency if they are found inn the states shown in the figures at four different points of time.

The total energy of a particle executing simple harmonic motion is

The phase of a particle executing simple harmonic motion is pi/2 when it has

If a particle is executing simple harmonic motion, then acceleration of particle

Two bodies performing S.H.M. have same amplitude and frequency. Their phases at a certain instant are as shown in the figure. The phase difference between them is

The maximum seperation between two particles executing simple harmonic motion of the equal amplitude and same frequency along the same straight line and about the same mean position, is sqrt(3) times the amplitude of oscillation. IF the phase difference between them is phi , determine 2pi//phi .

A particle is executing simple harmonic motion with an amplitude of 0.02 metre and frequency 50 Hz . The maximum acceleration of the particle is

A particle executing simple harmonic motion with an amplitude A and angularr frequency omega . The ratio of maximum acceleration to the maximum velocity of the particle is