A uniform U-tube contains a very slightly mobile liquid to a height of 50 cm in each limb. If the liquid in one lime is depressed and then released, find the period of oscialltion of the liquid in the tube.

Find time period of liquid column of length l in the shown tube.

A vertical U-tube contains liquid of uniform density upto a height of 3 cm. If the liquid in one arm is depressed and then released, it performs S.H.M. in the tube. Calculate its time period of oscillations. Assume U-tube to be of uniform cross section. Take, g = 980 cm//s^(2)

A vertical U-tube of uniform cross-section contains water upto a height of 30 cm. show that if the water in one limb is depressed and then released, its up and down motion in the two limbs of the tube is simple harmonic and calculate its time-period.

Motion of an oscillating liquid column in a U-tube is

Motion of an oscillating liquid column in a U-tube is

Motion of an oscillating liquid column in a U-tube is

Motion of an oscillating liquid column in a U-tube is :

When a capillary tube of radius r is immersed in a liquid of density rho, the liquid rises to a height h in it. If m is the mass of the liquid in the capillary tube, find the potential energy of this mass of the liquid in the tube.

STATEMENT-1 : The height of a liquid column in a U -tube is 0.3 m . If the liquid in one of the limbs is depressed, and then released, the time period of liquid column will be 1.1 sec . STATEMENT-2 : this follows from the relation. T = 2pisqrt(h)/(g)