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A rubber cord of force constant k = 100 ...

A rubber cord of force constant k = 100 N/m and l=1m is attached to a particle of mass m = 1kg at one end and fixed to a vertical wall at the other. The body is displaced by `x_(0)` = 25cm so as to stretch the cord and then released. Calculate the time particle takes to reach the wall.

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The correct Answer is:
`sqrt((m)/(k))((pi)/(2)+(l)/(x_(0)))=0.56s`
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