A simple pendulam loses 50 s in a day when taken to the bottom of a mine. Find the depth of the moine. (Radius of the earth=6400 km)

A simple pendulam loses 50 s when taken to the top of a hill. Find the height of the hill. Radiius of earth = 6400 km.

Find out the capacitance of the earth ? (Radius of the earth = 6400 km)

A pendulum clock, which keeps correct time at sea level, loses 15s per day when taken to the top of a mountain. If the radius of the earth is 6400km , the height of the mountain is

Assuming that the earth is a sphere of uniform mass density, what is the percentage decreases in the weight of a body when taken to the end of the tunned 32 km below the surface of the earth? (Radius of earth = 6400 km)

A mine worker measures his weight inside a mine and finds that it has decreased by 0.05% of that on the surface of the Earth. Then,find the depth of the mine (Take the radius of the Earth = 6400 km and acceleration due to gravity on the surface of the Earth, g = 9.8 ms^(-2) ).

Find the percentage decrease in the weight of the body when taken to a depth of 32 km below the surface of earth. Radius of the earth is 6400 km .

Find the percentage decrease in the wight of the body when taken to a heigh of 16 km above the surface of Earth. Radius of the earth is 6400 km .

Calculate the percentage decrease in the weight of a body when it is taken to a height of 40 km above the earth's surface. Radius of earth = 6,400 km.

Find the percentage decrease in the weight of a body when taken 16 km below the surface of the earth. Take radius of the earth is 6400 km.

If g on the surface of the earth is 9.8ms^(-2) , its value of a depth of 3200 km, (Radius of the earth =6400 km) is