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A hollow light cylinder of length 10 cm ...

A hollow light cylinder of length 10 cm is suspended by a string of length 95 cm. Calculate the time period of this simple pendulam when the cylinder is
completely filled with mercury, (ii) half filled with mercury, (g=9.81 `ms^(-2)`)

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The correct Answer is:
(i) 2.006 s, (ii) 2.031 s
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NN GHOSH-SIMPLE AND COMPOUND PENDULUM-Exercise
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  2. A hollow light cylinder of length 10 cm is suspended by a string of le...

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  3. A faultyu seconds pendulems loses 9 s per day. Find the required alter...

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  4. A simple pendulam which beats a second on the surface of the earth whe...

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  5. A simplependulam beats seconds on the earth (g=9.8 ms^(-2)) is taken t...

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  6. The bob of a simple pendulam is of mass 50 g and radius 1.5 cm. It is ...

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  7. A simple pendulam loses 50 s when taken to the top of a hill. Find the...

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  8. Two simple pendulams of lengths 1 and 1.1 m rerspectively start swingi...

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  9. A simple pendulam of period 2 s is suspended from the cielieng of a ca...

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  10. A simple pendulam of length l is suspended from the ceiling of a movi...

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  11. Show that the period of a simple pendium is given by T=2pi sqrt((m)/(m...

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  12. Show that the time period of a simplw pendulam of infinite length is g...

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  13. A simple pendulum is secrured in a flat railway car and set oscillatio...

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  14. A pendulum clock is mounted in an elevator car which starts going up w...

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  15. A body of mass 0.42kg oscillates about a horizontal xis distant 0.25mm...

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  16. A uniform square amina of side 0.3m oscillates ina vertiacla plane abo...

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  18. A thin uniform rod of lenth 120cm is made to oscillate about an axis p...

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  19. A uniform square lamina of side 10cm is hung up by a corner and swings...

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