A simple pendulam loses 50 s when taken ...

A simple pendulam loses 50 s when taken to the top of a hill. Find the height of the hill. Radiius of earth = 6400 km.

Text Solution

Verified by Experts

The correct Answer is:

3.7 km

Topper's Solved these Questions

SIMPLE AND COMPOUND PENDULUM
NN GHOSH|Exercise Exercise|24 Videos
SECOND LAW OF THERMODYNAMICS
NN GHOSH|Exercise All Questions|7 Videos
SIMPLE HARMONIC MOTION
NN GHOSH|Exercise Eexercies|39 Videos

Similar Questions

Explore conceptually related problems

A simple pendulam loses 50 s in a day when taken to the bottom of a mine. Find the depth of the moine. (Radius of the earth=6400 km)

Find out the capacitance of the earth ? (Radius of the earth = 6400 km)

A pendulum clock, which keeps correct time at sea level, loses 15s per day when taken to the top of a mountain. If the radius of the earth is 6400km , the height of the mountain is

Assuming that the earth is a sphere of uniform mass density, what is the percentage decreases in the weight of a body when taken to the end of the tunned 32 km below the surface of the earth? (Radius of earth = 6400 km)

A simple pendulam which beats a second on the surface of the earth where g=9.8 ms^(-2) is taken to the top of a hill where it is found to lose 2 s in an hour, What is the hight of the hill ?(Radius of the earth = 6.

Calculate the percentage decrease in the weight of a body when it is taken to a height of 40 km above the earth's surface. Radius of earth = 6,400 km.

Find the percentage decrease in the weight of the body when taken to a depth of 32 km below the surface of earth. Radius of the earth is 6400 km .

Find the velocity of a satellite at height 80 km from earth. If the radius of earth is 6400 km

Find the percentage decrease in the wight of the body when taken to a heigh of 16 km above the surface of Earth. Radius of the earth is 6400 km .

A particle is projected from the surface of earth with intial speed of 4 km/s. Find the maximum height attained by the particle. Radius of earth = 6400 km and g = 9.8 m//s^(2)

NN GHOSH-SIMPLE AND COMPOUND PENDULUM-Exercise

A simplependulam beats seconds on the earth (g=9.8 ms^(-2)) is taken t...
Text Solution
|
The bob of a simple pendulam is of mass 50 g and radius 1.5 cm. It is ...
Text Solution
|
A simple pendulam loses 50 s when taken to the top of a hill. Find the...
Text Solution
|
Two simple pendulams of lengths 1 and 1.1 m rerspectively start swingi...
Text Solution
|
A simple pendulam of period 2 s is suspended from the cielieng of a ca...
Text Solution
|
A simple pendulam of length l is suspended from the ceiling of a movi...
Text Solution
|
Show that the period of a simple pendium is given by T=2pi sqrt((m)/(m...
Text Solution
|
Show that the time period of a simplw pendulam of infinite length is g...
Text Solution
|
A simple pendulum is secrured in a flat railway car and set oscillatio...
Text Solution
|
A pendulum clock is mounted in an elevator car which starts going up w...
Text Solution
|
A body of mass 0.42kg oscillates about a horizontal xis distant 0.25mm...
Text Solution
|
A uniform square amina of side 0.3m oscillates ina vertiacla plane abo...
Text Solution
|
Calculate the time period of oscillation of a uniform recctangular pla...
Text Solution
|
A thin uniform rod of lenth 120cm is made to oscillate about an axis p...
Text Solution
|
A uniform square lamina of side 10cm is hung up by a corner and swings...
Text Solution
|
A disc of metal of raidus r with its plane vetical can be made to swin...
Text Solution
|
A uniform cirucular disc of 25cm radius oscillates in its own plane ab...
Text Solution
|
In a Kater's pendulum the time periods about the knife edges at distan...
Text Solution
|
A Kater's pendulum of mass 5kg gives an equal oscillation period of 2....
Text Solution
|
A compound pendulum consists of a rigid light rod having two spherical...
Text Solution
|