Show that the period of a simple pendium is given by `T=2pi sqrt((m)/(m),(1)/(g))` where m is the 'internial mass' and m is the 'gravitional mass' of the bob.

Find the dimensions of K in the relation T = 2pi sqrt((KI^2g)/(mG)) where T is time period, I is length, m is mass, g is acceleration due to gravity and G is gravitational constant.

If the inertial mass m_(1) of the bob of a simple pendulum of length 'l' is not equal to the gravitationalmass m_(g) , then its period is

What is the dimensional formula of (a) volume (b) density and (c ) universal gravitational constant 'G' . The gravitational force of attraction between two objects of masses m and m separated by a distance d is given by F = (G m_(1) m_(2))/(d^(2)) Where G is the universal gravitational constant.

If the speed v of a particle of mass m as function of time t is given by v=omegaAsin[(sqrt(k)/(m))t] , where A has dimension of length.

Find the dimensions of the quantity q from the expression T = 2pi sqrt((ml^3)/(3Yq)), where T is time period of a bar of length l, mass m and Young's modulus Y.

In the previous problem, if time period, T =2(pi) m/(BQ) where Q is the charge of the particle and m is its mass, the ratio of time spent by the particle in field when (theta) is positive to when (theta) is negative is given by

The time period of oscillation of a simple pendulum having length Land mass off the bob mis given as T. Ifthe length of the pendulum is increased to 4L and the mass of the bob is increased to 2m, then which one of the following is the new period of oscillation?

Find the dimensions of the quantity q from the expression : T = 2pi sqrt((ml^3q)/(5Y)), Where T is tiem period of a bar of length I, mass m and Young's modulus Y.

The time period of a pendulum of length 'l' and mass of the bob 'm' is T. Time period of a pendulum with mass of the bob 2m and length l is ______.