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A body of mass 0.42kg oscillates about a...

A body of mass 0.42kg oscillates about a horizontal xis distant 0.25mm frim its CG. If the length of am equivalent simple pendulum be 0.35m, find its moment of inertia about its axis of suspension, and its period of oscillation. `(g=9.8ms^(-2))`
`"[Hint" L=(k^(2))/(l)+l,l=mk^(2)+ml^(2)."]"`

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The correct Answer is:
`0.03675kgm^(2), 1.1874s`
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