If a number of little droplets of water, each of radius `r`, coalesce to form a single drop of radius `R`, show that the rise in temperature will be given by `(3T)/J(1/r-1/R)` where `T` is the surface tension of water and `J` is the mechanical equivalent of heat.

If a number of little droplets of water each of radius r, coalesce to form a single drop of radius R, show that the rise in temperature will be given by Delta0=(3sigma)/(J)((1)/(r)-(1)/(R)) Where sigma is the surface tension of water and J is the mechanical equivalent of heat.

n number of water droplets, each of radius r , coalese, to form a single drop of radius R . The rise in temperature d theta is

A number of droplets, each of radius r , combine to form a drop of radius R . If T is the surface tension, the rise in temperature will be

n droplets of equal size and each of radius r coalesce to form a bigger drop of radius R. the energy liberated is equal to

Several spherical drops of a liquid each of radius r coalesce to form a single drop of radius R. If T is the surface tension, then the energy liberated will be -

Several spherical deops of a liquid each of radius r coalesece to from a single drop of radius R. If T is the surface tension, then the energy liberated will be

Eight droplets of water each of radius 0.5 mm when coalesce into single drop , then the change in surface energy will be ,

n' droplets of equal of radius r coalesce to form a bigger drop of radius R. The energy liberated is equal to ( T = Surface tension of water )

A certain number of spherical drops of a liquid of radius r coalesce to form a single drop of radius R and volume V . If T is the surface tension of the liquid, then