Block C shown in figure-1.79 is going down at acceleration `2 m//s^(2)`. Find the acceleration of blocks A and B.

If block B shown in figure-l.78(a) is going down with acceleration 5 m//s^(2) , find the acceleration of the block A. All pulleys and strings are ideal. Radii ratio for the two step pulleys are 1 : 3 : 5 and 1 :2 .

If the wedge A shown in figure-1.93, is moving toward left with acceleration 3 m/s^(2) , find the net acceleration of block B which is constrainedtoslide along the wedge surface. (theta=30^(@))

Block A is kept on block B as shown in figure. It is known that acceleration of block A is 2 m//s^(2) towards right and acceleration of block B is 3 m//s^(2) towards right under the effect of unknown forces. Direction of friction force acting on A by B (mu_(AB) = 0.3)

A force F=75 N is applied on a block of mass 5 kg along the fixed smooth incline as as shown in the figure. Here gravitational acceleration g = 10 m s^(-2) . The acceleration of the block is

The elevator shown in figure is descending, with an acceleration of 2 m//s^(2) . The mass of block A is 0.5 kg. the force exerted by block A on block B is (mass of block B is 1 kg)

In an arrangement shown in the figure, the acceleration of block A and B are given-

The elevator shown in fig. is descending with an acceleration of 2 m//s^(2) . The mass of block A is 0.5 kg. The force exerted by the block A on the block B is

In figure shown if 2 kg block is moving at an acceleration 2 m//s^(2) , find the elongationin spring and acceleration of 4 kg block at this instant. Take g= 10m//s^(2) . [0.012 m, 2 m//s^(2)]

In the arrangement shown in the fig. the block of mass m lies on the wedge. Wedge is moving with acceleration a = 5 m/sec . Find the wedge acceleration of the block with respect to wedge.