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A particle is moving on a circular path ...

A particle is moving on a circular path of radius R with uniform angular speed `omega`. The magnitude of average velocityof particle during time `t=0` to `t=(2pi)/(3 omega)`:

A

`sqrt(3)/2 (omega R)/pi`

B

`3/2 (omegaR)/pi`

C

`(3sqrt(3))/(2) (omegaR)/pi`

D

`2/3 (omegaR)/(pi)`

Text Solution

Verified by Experts

The correct Answer is:
C
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