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The position of a particle moving in a s...

The position of a particle moving in a straight line is given by
`x=3t^(3)-18t^(2)+36t`
Here, x is in m and t in second. Then

A

direction of velocity and acceleration both change at `t=2s`

B

the distance travelled by particle is equal to magnitude of displacement for `t=0` to `t=5s`

C

the speed of particle is decreasing in `t=0` to `t=2s` then it is increasing for `t gt 2`

D

The magnitudes of velocity and acceleration are equal at `t=0`

Text Solution

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The correct Answer is:
B, C, D
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