The speed of a train increases at a constant rate `alpha` from zero to v and then remains constant for an interval and finally decreases to zero at a constant rate `beta`. The total distance travelled by the train is l. The time taken to complete the journey is t. Then,

the velcoity of a trian incrreases at a constant rate alpha from 0 to v and then remains constant for same interval and then finally decreases to zero at constant rate beta .if the total distance coverd by the the particle x,then show that the total time taken will be tx/v+v/2[1/alpha + 1/beta] .

The speed of a car increases uniformly from zero to 10ms^-1 in 2s and then remains constant (figure) a. Find the distance travelled by the car in the first two seconds. b. Find the distance travelled by the car in the next two seconds. c. Find the total distance travelled in 4s .

A left storing from rest assends with constants acceleration 'a', then with a constant velcoity and finally stops under a constant retardation 'a'. If the total distance assended is 'x' and the total time taken is 't',show that the time during which the left is assending with constant vlocity is sqrt(t^(2)-(4x)/a

A car, starting from rest, accelerates at the rate f through a distance s, then continues at constant speed for time t and then decelerates at the rate f/ 2 to come to rest. If the total distance travelled is 15 s, then

When the speed remains constant, the distance travelled is ______proportional to the time

A train accelerates from at the constant rate b for time t_(2) at a constant rate a and then it retards at the comes to rest. Find the ratio t_(1) // t_(2) .

A car accelerates from rest at a constant rate alpha for sometime , after which it decelerates at a constant rate beta and comes to rest. If T is the total time elapsed, the maximum velocity acquired by the car is

A car,starting from rest, accelerates at the rate f through a distance s, then continuous at constant speed for time t and then decelerates at the rate f/2 come to rest. If the total distance traversed is 5 s,then :

A lift ascends with constant acceleration a=1ms^(-2) , then with constant velocity and finally, it stops under constant retardation a=1ms^(-2) . If total distance ascended by the lift is 7 m, in a total time of the journey is 8 s. Find the time (in second) for which lift moves with constant velocity.