Home
Class 11
PHYSICS
An elevator platform is going up at a sp...

An elevator platform is going up at a speed of `20 m//s` and during its upward motion a small ball of `50 g` mass, falling in downward direction, strikes the platform at speed `5 m//s`. Find the speed with which the ball rebounds.

Promotional Banner

Topper's Solved these Questions

  • LINEAR MOMENTUM & ITS CONSERVATION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Practive Exercise|28 Videos
  • LINEAR MOMENTUM & ITS CONSERVATION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Discussio Q|28 Videos
  • KINEMATICS

    PHYSICS GALAXY - ASHISH ARORA|Exercise Unsolved Numerical Pro.|83 Videos
  • NEWTONS LAWS OF MOTION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Unsolved Numerical Problem|81 Videos

Similar Questions

Explore conceptually related problems

An elevator platform is going up at a speed 20 ms^(-1) and during its upward motion a small ball of 50 g mass falling in downward direction strikes the platform elastically at a speed 5 ms^(-1) . Find the speed (in ms^(-1) ) with which the ball rebounds.

A ball is thrown up at a speed of 4.0 m/s. Find the maximum height reached by the ball. Take g=10 m//s^2 .

A highly elastic ball moving at a speed of 3 m//s approaches a wall moving towards it with a speed of 3 m//s . After the collision. the speed of the ball will be

A ball moving vertically downward with a speed of 10 m//s collides with a platform. The platform moves with a velocity of 5 m//s in downward direction. If e = 0.8 , find the speed (in m//s ) of the ball just after collision.

A ball falls from a height of 5 m and strikes a lift which is moving in the upward direction with a velocity of 1 m s^(-1) , then the velocity with which the ball rebounds after collision will be

Two balls are projected vertically upward with same speed 35 m/s in 3s interval. Find height at which both balls collide.

A platform is moving upwards with a constant acceleration of 2 m s^-2 . At time t = 0 , a boy standing on the platform throws a ball upwards with a relative speed of 8 m s^-1 . At this instant, platform was at the height of 4 m from the ground and was moving with a speed of 2 m s^-1 . Take g = 0 m s^-2 . Find (a) when and where the ball strikes the platform. (b) the maximum height attained by the ball from the ground. ( c) the maximum distance of the ball from the platform.

A body falling with a speed of 2m/s strikes the floor and rebounds with a speed of 1 m/s. The loss of kinetic energy is

A ball is thrown up with a speed of 15 m/s . How high wiil it go before it begins to fall ? (g=9.8 m//s^(2)