A sphere of mass `m_(1)` in motion hits directly another sphere of mass `m_(2)` at rest and sticks to it, the total kinetic energy after collision is `2//3` of their total K.E. before collision. Find the ratio of `m_(1) : m_(2)`.

A sphere of mass '2m' gm collides with a stationary sphere of '3m' gm and sticks to it.Then the loss in kinetic energy during collision is

An object of mass m_(1) moving with speed v collides with another object of mass m_(2) at rest and stick to it. Find the impulse imparted to the second object.

A spherical ball of mass m_(1) colliddes head on with another ball of mass m_(2) at rest . The collision is elastic . The fraction of kintic energy lost by m_(1) is :

A particle of mass m moving with speed u collides perfectly inelastically with another particle of mass 2m at rest. Find loss of kinetic energy of system in the collision.

A solid sphere of mass 1 kg rolls on a table with linear speed 1 m/s. Its total kinetic energy is

A body of mass m_(1) moving at a constant speed undergoes an elastic head on collision with a body of mass m_(2) initially at rest. The ratio of the kinetic energy of mass m_(1) after the collision to that before the collision is -

A body of mass m_(1) collides elastically with another body of mass m_(2) at rest. If the velocity of m_(1) after collision is (2)/(3) times its initial velocity, the ratio of their masses is :

A mass of 3M moving at a speed v collides with a mass of M moving directly towards it, also with a speed v .If the collision is completely elastic, the total kinetic energy after the collision is K_(e) .If the masses stick together,the total kinetic energy after the collision is K_(s) .What is the ratio (K_(e))/(K_(s)) ?