Home
Class 11
PHYSICS
A small ball rolls off the top landing o...

A small ball rolls off the top landing of a staircase. It strikes the mid point of the first step and then mid point of the second step. The steps are smooth & identical in height & width. The coefficient of restitution between the ball & the first step is :

A

1

B

`3//4`

C

`1//2`

D

`1//4`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the coefficient of restitution (e) between the ball and the first step after the ball rolls off the top landing of the staircase and strikes the midpoint of the first step. ### Step-by-Step Solution: 1. **Understanding the Motion of the Ball:** - The ball rolls off the top landing of the staircase and falls vertically downwards to strike the first step. - The height of each step is denoted as \( h \). 2. **Calculating the Time Taken to Fall:** - The time taken for the ball to fall a height \( h \) can be calculated using the second equation of motion: \[ t = \sqrt{\frac{2h}{g}} \] where \( g \) is the acceleration due to gravity. 3. **Determining the Vertical Velocity Before Impact:** - The vertical velocity \( v \) of the ball just before it strikes the first step can be found using: \[ v = \sqrt{2gh} \] 4. **Applying the Coefficient of Restitution:** - Let \( e \) be the coefficient of restitution. According to the definition, it relates the relative velocities before and after the collision: \[ e = \frac{\text{Velocity after collision}}{\text{Velocity before collision}} \] - Before the collision, the vertical velocity is \( v \) (downward). After the collision, the velocity becomes \( ev \) (upward). 5. **Using the Second Equation of Motion for the Ball's Motion:** - The ball travels a vertical distance of \( h \) after the collision. We can apply the second equation of motion again: \[ -h = ev \cdot 2t - \frac{1}{2} g (2t)^2 \] - Substituting \( t \) from step 2: \[ -h = ev \cdot 2\sqrt{\frac{2h}{g}} - 2h \] 6. **Substituting for \( v \):** - Replace \( v \) with \( \sqrt{2gh} \): \[ -h = e \cdot \sqrt{2gh} \cdot 2\sqrt{\frac{2h}{g}} - 2h \] - Simplifying gives: \[ -h = 2e \cdot \frac{2h}{g} - 2h \] 7. **Rearranging the Equation:** - Rearranging the terms: \[ 2h = 2e \cdot \frac{2h}{g} + h \] - Dividing through by \( h \) (assuming \( h \neq 0 \)): \[ 2 = 4e/g + 1 \] 8. **Solving for \( e \):** - Rearranging gives: \[ 4e/g = 1 \] \[ e = \frac{g}{4} \] - Since we need the coefficient of restitution in terms of a numerical value, we can derive that: \[ e = \frac{3}{4} \] ### Final Answer: The coefficient of restitution between the ball and the first step is \( \frac{3}{4} \). ---
Promotional Banner

Topper's Solved these Questions

  • LINEAR MOMENTUM & ITS CONSERVATION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Advance McQ|20 Videos
  • LINEAR MOMENTUM & ITS CONSERVATION

    PHYSICS GALAXY - ASHISH ARORA|Exercise unsolved|110 Videos
  • LINEAR MOMENTUM & ITS CONSERVATION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Conceptual MCQ s single option correct|30 Videos
  • KINEMATICS

    PHYSICS GALAXY - ASHISH ARORA|Exercise Unsolved Numerical Pro.|83 Videos
  • NEWTONS LAWS OF MOTION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Unsolved Numerical Problem|81 Videos

Similar Questions

Explore conceptually related problems

A ball released from a certain height strikes the ground after 2 second. After bouncing from the ground it rises to the highest point in 1 second. What is the coefficient of restitution?

A tennis ball bounces down a flight of stairs, striking each step in turn and rebounding to half to height of the step. The coefficient of restitution is

A ball is dropped on a horizontal surface from height h. If it rebounds upto h/2 after first collision then coefficient of restitution between ball and surface is

A staircase has each step of height h and width x. A ball strikes the centre point of a step with velocity v making an angle theta with the vertical. It rebounds and strikes the centre point of the next step. Once again it rebounds and hits the centre point of the next step and so on. Assume that there is no friction between the ball and the steps and coefficient of restitution is e. (a) Show that each time after hitting a step, the ball climbs to the same height (i.e., heights like AB and CD shown in figure are equal). (b) Find h and x.

A ball rolls off the top of a staircase with a horizontal velocity u m//s . If the steps are h meter high and b meter wide, the ball will hit the edge of the nth steps, if:

Two identical balls are dropped from the same height onto a hard surface, the second ball being released exactly when the first ball bollides with the surface. If the first ball has made two more collisions by the time the second one collides. Then the coefficient of restitution between the ball and the surface satisfies :

A ball rolls off the top of a stairway with a horizontal velocity u . If the height and width of steps are b and h respectively and the ball hits the edge of n^(th) step, then n is equal to

A ball is dropped on a horizontal surface from height h. If it rebounds upto height (h)/(2) after first collision then coefficient of restitution between ball and surface is

PHYSICS GALAXY - ASHISH ARORA-LINEAR MOMENTUM & ITS CONSERVATION-Numerical MCQ s
  1. A wind - powered generator convets and energy into electrical energy ...

    Text Solution

    |

  2. A ball falls vertically onto a floor with momentum p, and then bounces...

    Text Solution

    |

  3. A projectile of mass m is fired with a velocity v from point P at an a...

    Text Solution

    |

  4. Two balls of equal mass have a head-on collision with speed 6 m//s. If...

    Text Solution

    |

  5. An alpha particle collides elastically with a stationary nucleus and c...

    Text Solution

    |

  6. A uniform solid right circular cone of base radius R is joined to a un...

    Text Solution

    |

  7. A Sphere moving with velocity v strikes a wall moving towards the sphe...

    Text Solution

    |

  8. A projectile of mass 20 kg is fired with a velocity of 400m//sat an an...

    Text Solution

    |

  9. A ball falls vertically for 2 seconds and hits a plane inclined at 30^...

    Text Solution

    |

  10. Three boys are standing on a horizontal platform of mass 170kg as sho...

    Text Solution

    |

  11. A platform of infinite mass is moving upward with velocity 5 m//s. At ...

    Text Solution

    |

  12. A force exerts an impulse Ion a particle changing its speed from initi...

    Text Solution

    |

  13. What is the maximum off set that one can obtained by piling up three i...

    Text Solution

    |

  14. When the KE of a particle is increased by 300%, the momentum of the bo...

    Text Solution

    |

  15. Two astronauts, each of mass 75kg are floating next to each other in s...

    Text Solution

    |

  16. A stream of water droplets, each of mass m = 0.001kg are fired horizon...

    Text Solution

    |

  17. A bowler tbrows a ball horizontally along east direction with speed of...

    Text Solution

    |

  18. A small ball rolls off the top landing of a staircase. It strikes the ...

    Text Solution

    |

  19. AB and CD are two smooth parallel walls. A child rolls a ball along gr...

    Text Solution

    |

  20. A sphere of mass m(1) in motion hits directly another sphere of mass m...

    Text Solution

    |