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Velocity of a particle of mass 2 kg chan...

Velocity of a particle of mass `2 kg` change from `vecv_(1) =-2hati-2hatjm/s` to `vecv_(2)=(hati-hatj)m//s` after colliding with as plane surface.

A

the angle made by the plane surface with the positive x-axis is `90^(@) + "tan"^(-1)((1)/(3))`

B

the angle made by the plane surface with the positive x-axis is `"tan"^(-1)((1)/(3))`

C

the direction of change in momentum makes an angle `"tan"^(-1)((1)/(3))`with the `+ve` x-axis

D

the direction of change in momentum makes an angle `90^(@) + "tan"^(-1) ((1)/(3))` with the plane surface

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The correct Answer is:
A, C
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