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A rough wedge of mass M is free to move ...

A rough wedge of mass M is free to move on a smooth horizontal plane as shown in figure-5.69.The uniform cylinder of mass m is placed on the wedge and it begins to roll down without slipping . Show that the acceleration of cylinder on the surface of wedge is given as
`a = (2g "sin"theta(m + M))/(m + 3M + 2msin^(2)theta)`

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PHYSICS GALAXY - ASHISH ARORA-RIGID BODIES AND ROTATIONAL MOTION-Unsolved Numerical
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