A student stands on a table rotating with an angular speed `omega` while holding two equal dumbbells at arm's length. With out moving anything else,the two dumbbells are dropped. What changes will be there in motion, if any? What would be the changes if he bring the dumbbells to keep in touch with his chest by folding his arms ? Explain

A man turns on a rotating table with an angular velocity omega . He is holding two equal masses at arm's. Without moving his arms, he just drops the masses. Then his angular velocity

A man stands in the middle of a rotating table which has an angular velocity omega He is holding two equal masses at arms lengtii ineach hand. Without moving his arms he just drops the two masses. How will be the angular speed of table get changed?

A student sits on a freely rotating stool holding dumbbells, each of mass 5.0 kg (Fig). When his arms are extended horizontally (Fig a), the dumbbells are 1.0 m from the axis of rotation and the student rotate with an angular speed of 1.0 rad//s . The moment of inertia of the student plus stool is 5.0 kg.m^2 and is assumed to be constant. The student pulls the dumbbells inward horizontally to a position 0.50 m from the rotationa are (Fig.) The new angular speed of the student is. .

A man stands on a rotating platform with his arms stretched holding a 5 kg weight in each hand. The angular speed of the platform is 1.2 rev s^-1 . The moment of inertia of the man together with the platform may be taken to be constant and equal to 6 kg m^2 . If the man brings his arms close to his chest with the distance n each weight from the axis changing from 100 cm to 20 cm . The new angular speed of the platform is.

A child is standing with his two arms outstretched at the centre of a turntable that is rotating about its central axis with an angular speed omega_0 . Now, the child folds his hands back so that moment of inertia becomes 3 times the initial value. The new angular speed is.

A child stands at the centre of a turn table with his two arms outstretched. The turn table is set rotating with an angular speed of 40 rpm. How much is the angular speed of the child, if he folds his hands back reducing the moment of inertia to (2//5) time the initial value ? Assume that the turn table rotates without friction. (b) Show that the child's new K.E. of rotation is more than the initial K.E. of rotation. How do you account for this increase in K.E. ?