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A particle of mass m is projected with a...

A particle of mass m is projected with a velocity `mu` at an angle of `theta` with horizontal.The angular momentum of the particle about the highest point of its trajectory is equal to :

A

`("mu"^(3)sin^(2)thetacostheta)/(3g)`

B

`(3"mu"^(3)sin^(2)thetacostheta)/(3g)`

C

`("mu"^(3)sin^(2)thetacostheta)/(2g)`

D

`(2"mu"^(3)sinthetacos^(2)theta)/(3g)`

Text Solution

Verified by Experts

The correct Answer is:
C
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