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A particle is projected at time t=0 from...

A particle is projected at time t=0 from a point P on the ground with a speed `v_0,` at an angle of `45^@` to the horizontal. Find the magnitude and direction of the angular momentum of the particle about P at tiem `t= v_0//g`

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The correct Answer is:
`"["(mv_(0)^(3))/(2sqrt2g)"]"`
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