A rod of mass m and length l is held ver...

A rod of mass m and length l is held vertically on a smooth horizontal floor. Now it is released from this position, find the speed of its centre of mass when it makes an angle `theta` with the vertical.

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The correct Answer is:

[`(sqrt(6gl)sin"(theta)/(2)costheta)/(sqrt1+3sin^(2)theta)`]

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