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The density of air in atomsphere decreas...

The density of air in atomsphere decreases with height and can be expressed by the relation.
`rho=rho_(0)e^(-Ah)`
Where `rho_(0)` is the density at sea-level, A is a constant and h is the height. Calculate the atmospheric pressure at sea -level. assume g to be constant.

Text Solution

Verified by Experts

The correct Answer is:
`9.8m//s^(2), rho_(0) =1.3 kg//m^(3)` and `A=1.2xx10^(-4) m^(-1)`
`1.06xx10^(5) N//m^(2)`
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