A large open top container of negligible mass and uniform cross sectional area `A` a has a small hole of cross sectional area `A//100` in its side wall near the bottom. The container is kept on a smooth horizontal floor and contains a liquid of density `rho` and mass `M_(0)`. Assuming that the liquid starts flowing out horizontally through the hole at `t=0`, calculate a the acceleration of the container and b its velocity when `75%` of the liquid has drained out.

Answer

[(i) `0.2 m//sec^(2)`, (ii) `10sqrt(((2m_(0))/(A rhog)))]`