A steel ball floats in a vessel with mercury. How will be volume of the part of the ball submerged in mercury change if a layer of water completely covering the ball is poured above the mercury? If `rho_(w), rho_(s)` and `rho_(m)` are the densities of water, steel and mercury, find the ratio of these two volumes in terms in of `rho_(w), rho_(s)` and `rho_(m)`.

Answer

`[[V_(0)/V_(1)=(1-rho_(w)//rho_(m))/(1-rho_(w)//rho_(s))]]`