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4x^2-4x+1...

`4x^2-4x+1`

Text Solution

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`p(x) = 4x^2-4x+1 `
To get the value of `x`, we will put `p(x) = 0`.
`=> 4x^2-4x+1 = 0`
`=> 4x^2-2x-2x+1 = 0`
`=>2x(2x-1)-1(2x-1) = 0`
`=>(2x-1)^2 = 0`
`=> x = 1/2`, which is the required value of `x`.
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