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int(3x^2)/sqrt(9-16x^6)dx...

`int(3x^2)/sqrt(9-16x^6)dx`

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Integrate the following function : int(3x^(2))/(sqrt(9-x^(6)))dx

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Knowledge Check

  • If int(1)/(sqrt(9-16x^(2)))dx=alphasin^(-1)(betax)+c , then alpha+(1)/(beta)=

    A
    1
    B
    `(7)/(12)`
    C
    `(19)/(12)`
    D
    `(9)/(12)`

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    int(x^(2))/(9+16x^(6))dx

    int(dx)/(sqrt(1-16x^2) =

    int(x)/(sqrt(9-x^(2)))dx

    If int(1)/(sqrt(9-16x^(2)))dx=alphasin^(-1)(betax)+c , then alpha+(1)/(beta)=

    (i) int(sinx)/(sqrt(4+ cos^(2) x)) dx " "(ii) int(x^(2))/(sqrt(9+x^(6)))dx

    (i) int(sinx)/(sqrt(4+ cos^(2) x)) dx " "(ii) int(x^(2))/(sqrt(9+x^(6)))dx

    int(x+3)/(sqrt(9-x^(2)))dx

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