Home
Class 12
MATHS
A curve is discribed by the relation ln(...

A curve is discribed by the relation `ln(x+y)=x e^y` . Find the tangent to the curve at (0, 1).

Promotional Banner

Similar Questions

Explore conceptually related problems

A curve is discribed by the relation ln(x+y)=xe^(y). Find the tangent to the curve at (0,1)

Equation of the tangent to the curve y=e^(x) at (0,1) is

The equation of the tangent to the curve y = e^(2x) at (0,1) is

Find tangent of curve y=x^(3)-x at x=1

Equation of the tangent to the curve y= log x at (1,0) is

Find the equation of the tangent to the curve y=sec x at the point (0,1)

Consider the curve 2y=3-x^2 Find the slope of the tangent to this curve at (x_1,y_1) .

Consider the curve y=e^(2x) What is the slope of the tangent to the curve at (0,1)

Find the slope of tangent to curve y=x+2log x at x=1.

Find the slope of tangent to curve y=x+2log x at x=1.