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lf (3a)^log3= (4b)^log4 and 4^loga=3^log...

lf `(3a)^log3= (4b)^log4` and `4^loga=3^logb` ,then a+b=

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`(3a)^(log3)=(4b)^(log4)`
`log[log(3a)]=log4[log(4b)]`
`log3[log3+loga]+log4[log4+logb]-(1)`
`4^(loga)=3^(logb)`
`logalog4=logblog3`
`loga=(logblog3)/(log4)-(2)`
`log3[log3+(logblog3)/(log4)]=log4[log4+logb]`
`(log3)^2[1+(logb)/(loga)]=log4[log4+logb]`
...
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