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[2times2" 2815A zul "[[5,-7],[-2,3]]A=[[...

[2times2" 2815A zul "[[5,-7],[-2,3]]A=[[-16,-6],[7,2]]" an "],[A=]

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The matrix X for which [[1,-4],[ 3,-2]]X=[[-16-,6],[ 7 ,2]] is a. [[-2, 4],[-3, 1]] b. [[-1/5, 2/5],[-3/(10),1/5]] c. [[-16, 16],[ 7 ,2]] d. [[6, 2],[(11)/2, 2]]

The matrix X for which [[1,-4],[ 3,-2]]X=[[-16-,6],[ 7 ,2]] is a. [[-2, 4],[-3, 1]] b. [[-1/5, 2/5],[-3/(10),1/5]] c. [[-16, 16],[ 7 ,2]] d. [[6, 2],[(11)/2, 2]]

Find the matrix X such that , X[{:(5,-7),(-2,3):}]=[{:(-16,-6),(7,2):}] .

The matrix X for which [1-4 3-2]X=[-16-6 7 2] is [-2 4-3 1] b. [-1/5 2/5-3/(10)1/5] c. [-16 16 7 2] d. [6 2(11)/2 2]

The matrix X for which [1-4 3-2]X=[-16-6 7 2] [-2 4-3 1] (b) [-1/5 2/5(-3)/(10)1/5] [6 2(11)/2 2] (d) [-16-6 7 2]

The matrix X for which [1-4 3-2]X=[-16-6 7 2] [-2 4-3 1] (b) [-1/5 2/5(-3)/(10)1/5] [6 2(11)/2 2] (d) [-16-6 7 2]

I: If A=[(0,1,2),(2,3,4),(4,5,-6)],B=[(-1,2,3),(0,1,0),(0,0,-1)] then 4A-5B=[(5,-6,-7),(8,7,16),(16,20,-19)] II:If A=[(1,2,3),(3,2,1)]B=[(3,2,1),(1,2,3)] then 3B-2A=[(7,2,-3),(-3,2,7)]

Solve : -2/3 times 3/5 + 5/2 - 3/5 times 7/6

Evaluate |{:(2, 7, 24), (6, 16, 72), (5, 9, 60):}|

If mode of data 2,3,4,5,5,5,6,7,7,7,x and 2 is 7 then x=