If 27 abc> (a+b+c)^3 and 3a +4b +5c=12 ...

If `27 abc> (a+b+c)^3 and 3a +4b +5c=12` then `1/a^2+1/b^3+1/c^5=10`, where a, b, c are positive real numbers. Statement-2: For positive real numbers `A.M.>= G.M.`

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