[x+y+z=3],[2x-y+z=2],[x-2y+3z=2]

The equations x+2y-z=3, 3x-y+2z=1, 2x-2y+3z=2 have

Statement - I The soluton of the system of equations 2x-y+3z=9,x+y+z=6,x-y+z=2 is x=1,y=2,z=3 Statement - II : The solution of the system of equations x+2y-z=3,3x=y+2z=1 , 2x-2y+3z=2 is x=-1,y=4,z=4 Which of the above Statement(s) is true ?

Prove that |[x, y, z],[x^2, y^2, z^2], [x^3, y^3, z^3]|=xyz(x-y)(y-z)(z-x)

Show that : |[x, y, z ],[x^2,y^2,z^2],[x^3,y^3,z^3]|=x y z(x-y)(y-z)(z-x)dot

Prove that |[[x,y,z],[x^2,y^2,z^2],[x^3,y^3,z^3]]|= xyz (x-y)(y-z)(z-x)

The augmented matrix of x+y+z=6, 2x-y+z=3, 2y-z+x=2 is

Show that Delta=|[(y+z)^2, x y , z x],[ x y, (x+z)^2, y z],[ x z, y z, (x+y)^2]|=2 x y z(x+y+z)^3

x+2y-3z=0,3x+3y-z=5,x-2y+2z=1

x+y+z=4 2x-y+z=-1 2x+y-3z=-9

Solve: 2x-y+z=4,x+3y+2z=12,3x+2y+3z=16