" (i) "x+2y+1=0,2x-3y-12=0

Solve by cross multiplication x+2y+1=0 ,2x-3y-12=0

Solve the following system of equations by method of cross-multiplication: x+2y+1=0,quad 2x-3y-12=0

Solve the following system of equations by method of cross-multiplication: x+2y+1=0,\ \ \ \ 2x-3y-12=0

For the circle x^(2)+y^(2)-2x-4y-4=0 ,the lines 2x+3y-1=0,2x+y-1=0 are

Using the method of integration,find the area of the region bounded by the following lines 3x-y-3=0,2x+y-12=0,x-2y-1=0

Find the solution of the pair of equations: x-y+1=0, 3x+2y-12=0

Find the value of a for which the lines 2x+y-1=0 2x+y-1=0 a x+3y-3=0 3x+2y-2=0 are concurrent.

If the equations 2x+3y+1=0,2x+y-1=0 and ax+2y-b=0 are consistent, then

All points lying inside the triangle formed by the points (1.3).(5,0) and (-1,2) satisfy (A)3x+2y>=0 (B) 2x+y-13>=0 (C) 2x-3y-12 =0