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" 9."(sin A+sin3A+sin5A+sin7A)/(cos A+co...

" 9."(sin A+sin3A+sin5A+sin7A)/(cos A+cos3A+cos5A+cos7A)=tan4A

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Prove that: (sin A+sin3A+sin5A+sin7A)/(cos A+cos3A+cos5A+cos7A)=tan4A

prove that (sinA+sin3A+sin5A+sin7A)/(cosA+cos3A+cos5A+cos7A)=tan4A

Prove that: (sinA+sin3A+sin5A+sin7A)/(cosA+cos3A+cos5A+cos7A)=tan4A

Prove that: (sinA+sin3A+sin5A+sin7A)/(cosA+cos3A+cos5A+cos7A)=tan4A

Prove that: (sinA+s in3A+sin5A+sin7A)/(cosA+cos3A+cos5A+cos7A)=tan4A

Prove that: (sinA+s in3A+sin5A+sin7A)/(cosA+cos3A+cos5A+cos7A)=tan4A

(sinA+sin3A+sin5A+sin7A)/(cosA+cos3A+cos5A+cos7A) is :

(sinA + sin3A) / (cosA + cos3A) = tanalpha, (cosA-cos2A) / (sinA + sin2A) = tanbeta, (sinA + sin3A + sin5A + sin7A) / (cosA + cos3A + cos5A + cos7A) = tan gamma , (cosA-cos5A-cos9A + cos13A) / (sinA-sin5A + sin9A-sin13A) = tandelta, then (a) alpha = 4beta (b) gamma = 2alpha (c) gamma = delta (d) none

(sin A + sin5A + sin9A) / (cos A + cos5A + cos9A) =

(sin3A+sin5A+sin7A+sin9A)/(cos3A+cos5A+cos7A+cos9A)=tan6A