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x=acostheta+bsintheta and y=asintheta-bc...

`x=acostheta+bsintheta` and `y=asintheta-bcostheta,` show that `y^2(d^2y)/(dx^2)-x(dy)/(dx)+y=0`

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x/acostheta+y/bsintheta=1, x/asintheta-y/bcostheta=1 then x^2/a^2+y^2/b^2=