Find the equation of the circle with tou...

Find the equation of the circle with touching both the axes and passing though the point `(2,9)`

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The equation of the circle with centre (3,2) touching y -axis is

`x^(2)+y^(2)+6 x+4 y-3=0`

`x^(2)+y^(2)-6 x-4 y+4=0`

`x^(2)+y^(2)-6 x+4 y+4=0`

`x^(2)+y^(2)+6 x+4 y+4=0`

The equation of the circle of radius one unit touching both the axes and lying in the second rant is

`x^(2)+y^(2)+2 x-2 y+1=0`

`x^(2)+y^(2)-2 x+2 y+1=0`

`x^(2)+y^(2)-2 x-2 y+1=0`

`x^(2)+y^(2)+2 x+2 y+1=0`

The equation of the circle touching the y -axis at the origin and passing through (b, c) is

`b(x^(2)-y^(2))=x(b^(2)-c^(2))`

`b(x^(2)-y^(2))=x(b^(2)+c^(2))`

`b (x^(2)+y^(2))=x(b^(2)+c^(2))`

`b(x^(2)+y^(2))=x(b^(2)-c^(2))`