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Find the area of the region in the first...

Find the area of the region in the first quadrant enclosed by X-axis and `x=sqrt(3)y` and the circle `x^2+y^2=4`.

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The correct Answer is:
`(pi)/(3)` sq. units.
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SUBHASH PUBLICATION-APPLICATIONS OF INTEGRALS-FIVE MARKS QUESTIONS WITH ANSWERS
  1. Find the area of the region bounded by the ellipse (x^2)/(16)+(y^2)/(9...

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  2. Find the area of the region bounded by the ellipse (x^2)/(4)+(y^2)/(9)...

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  3. Find the area of the region in the first quadrant enclosed by X-axis a...

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  4. Find the area of the smaller part of the circle x^2+y^2=a^2 cut-off by...

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  5. The are between x=y^2 and x=4 is divided into two equal parts by the l...

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  6. Find the area bounded by the curve x^2=4y" and the line " x=4y-2.

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  7. Find the area of the circle 4x^2+4y^2=9 which is interior to the parab...

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  8. Find the area bounded by the curve (x-1)^2+y^2=1" and "x^2+y^2=1.

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  9. Find the area of the region bounded by the curves y=x^2+2,y=x,x=0" and...

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  10. Using integration, find the area of region bounded by the triangle who...

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  11. Using integration find the area of the triangular region whose sides h...

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  12. Using the method of integration, find the smaller area enclosed by the...

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  13. Find the area of the region enclosed by the parabola x^2=y," the line ...

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  14. Using method of integration find the area bounded by the curve |x|+|y|...

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  15. Find the area of the region bounded by the parabola y=x^2" and "y= |x|...

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  16. Using the method of integration find the area of the triangle ABC, coo...

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  17. Find the area of the region y^2=4x" and "4x^2+4y^2=9.

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