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Find the area of the circle 4x^2+4y^2=9 ...

Find the area of the circle `4x^2+4y^2=9` which is interior to the parabola `x^2=4y`.

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The correct Answer is:
`=(sqrt(2))/(6)+(9)/(4) sin^(-1)((2sqrt(2))/(3))` sq. unit.
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SUBHASH PUBLICATION-APPLICATIONS OF INTEGRALS-FIVE MARKS QUESTIONS WITH ANSWERS
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