Find the equation of the plane through the line of intersection of the planes `x+y+z=1 " and " 2x+3y+4z=5` which is perpendicular to the plane `x-y+z=0`.

Find the equation of the plane passing through the line of intersection of the planes .x+ y+ z = 6 and 2x+ 3y+ 4z-5 = 0 and the point (1,1,1).

Find the equation of the plane through the intersection of the planes. 3x-y+2z=0 and x+y+z-2=0 and the point (2,2,1)

The equation of the plane through the intersection of the planes x+y+z=1 and 2x+3y-z+4=0 and parallel to x -axis is

Find the equation of the plane through the intersection of the planes 3x-y+2z-4=0 " and " z+y+z-2=0 and the point (2,2,1) .

Find the equation of the plane through the intersection of the planes 3x-y+2z-4=0, x+y+z-2=0 and the point (2,2,1)

The equation of the plane passing through the intersection of the planes x+2y+3z+4=0 and 4x+3y+2z+1=0 and the origin is

The equation of a plane passing through the line of intersection of the planes: x + 2y + 3z = 2 and x- y + z = 3 at a distance 2/sqrt3 from the point (3,1,-1) is :

Equation of the plane through P(1,2,3) and parallel to the plane x+2 y+5 z=0 is