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A crate of mass 20 kg is sliding across ...

A crate of mass 20 kg is sliding across a wooden floor. The coefficient of kinetic friction between the crate and the floor is 0.3.
Determine the magnitude of the friction force acting on the crate.

Text Solution

Verified by Experts

First draw a free- body diagram.

The normal force on the object balances the object's weight, so `F_(N)=mg=(20 kg)(10 m//s^(2))=200 N`. Therefore, `F_(f("kinetic"))= mu_(k) F_(N)=(0.3)(200 N)=60 N`.
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Knowledge Check

  • A crate of mass 100 kg is at rest on a horizontal floor. The coefficient of static friction between the crate and the floor is 0.4, and the coefficient of kinetic friction is 0.3 . A force F of magnitude 344 N is then applied to the crate, parallel to the floor. Which of the following is true ?

    A
    The crate will accelerate across the floor at `0.5 m//s^(2)`.
    B
    The static friction force, which is the reaction force to F as guaranteed by Newton 's Third Law, will also have a magnitude of 344 N.
    C
    The crate will slide across the floor at a constant speed of `0.5 m//s`.
    D
    The crate will not move.

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