Home
Class 12
PHYSICS
A block of mass M=4kg is moving with vel...

A block of mass M=4kg is moving with velocity V=6m/s toward a target block of mass=2kg, which is stationary (v=0). The object collide heat-on, and immediately after the collision, the speed of block m is 4 times the speed of block M.
Q. What is the speed of block M after the collision?

Text Solution

Verified by Experts

If we let V' be the speed of block M immediately after the collision, then the speed of block m will be 4V'. By applying conservation of linear momentum, we find that
total `p_("before")=`total`p_("after")`
`MV=MV'+m(4V')`
`(4)(6)=(4)(V')+(2)(4V')`
`V'=2m//s`
Therefore, the speed of block M immediately after the collision is 2m/s (and the speed of block m immediately after the collision is 8 m/s).
Promotional Banner

Topper's Solved these Questions

  • LINEAR MOMENTUM

    PRINCETON|Exercise COMPREHENSIVE DRILL|9 Videos

  • KINEMATICS

    PRINCETON|Exercise MCQ|9 Videos

  • MATH REVIEW

    PRINCETON|Exercise Solved Example|4 Videos

Similar Questions

Explore conceptually related problems

A block of mass 1 kg moving with a speed of 4 ms^(-1) , collides with another block of mass 2 kg which is at rest. The lighter block comes to rest after collision. The loss in KE of the system is

On a friction surface a block a mass M moving at speed v collides elastic with another block of same mass M which is initially at rest . After collision the first block moves at an angle theta to its initial direction and has a speed (v)/(3) . The second block's speed after the collision is

A block of mass m moving at a velocity upsilon collides head on with another block of mass 2m at rest. If the coefficient of restitution is 1/2, find the velocities of the blocks after the collision.

A block of mass m moving with a velocity v_(0) collides with a stationary block of mass M to which a spring of stiffness k is attached, as shown in Fig. Choose the correct alternative(s)

A bullet of mass m moving with velocity v strikes a block of mass M at rest and gets embedded into it. The kinetic energy of the composite block will be

A block of mass m moving at speed upsilon collides with another block of mass 2 m at rest. The lighter block comes to rest after the collision. Find the coefficient of restitution.

A bullet weighing 10 g and moving with a velocity 300 m/s strikes a 5 kg block of ice and drop dead. The ice block is kept on smooth surface. The speed of the block after the the collision is

A bullet of mass 0.01 kg and travelling at a speed of 500 ms^(-1) strikes a block of mass 2 kg which is suspended by a string of length 5 m . The centre of gravity of the block is found to raise a vertical distance of 0.2 m . What is the speed of the bullet after it emerges from the block?