`3^(1/4)xx6^(3/4)xx2^(5/4)`

Simplify and write in exponential form : a. [(2^(3))^(3)xx4^(5)]-:5^(5) b. (10xx4^(4)xx3^(3))/(6^(3)xx2^(5)xx15)

Simplify: (2^(1/2)xx3^(1/3)xx4^(1/4))/(10^(-2/3)xx5^(3/5))div(3^(4/3)xx5^(-7/5))/(4^(-3/5)xx6)

Find the number of zeroes in the product 1^(1)xx2^(2)xx3^(3)xx4^(4)xx5^(5)xx6^(6)xx…xx49^(49)

Simplify : a. 15^(7)-:5^(3) b. ((5^(4))^(3)xx2^(12))/(3^(12)) c. ((4^(3))^(2)xx5^(6))/(10^(6)) d. (2xx3^(4)xx2^(5))/(9xx4^(2)) e. (2^(2)xx3^(4)xx16)/(3^(2)xx32) f. (4^(5)xxa^(8)xxb^(16))/(4^(4)xxa^(7)xxb^(4))

{:("Quantity A","Quantity B"),(3^(3)xx9^(6)xx2^(4)xx4^(2),9^(3)xx3^(6)xx2^(2)xx4^(4)):}

The value of the infinite product 6(1)/(2)xx6^((2)/(4))xx6^((3)/(8))xx6(4)/(16)xx...

(2^((1)/(2))xx3^((1)/(3))xx4^((1)/(4)))/(10^(-(1)/(5))xx5^((3)/(5)))-:(3^((4)/(3))xx5^(-(7)/(5)))/(4^(-(3)/(5))xx6)=10

Evaluate [3/4xx((2/4)xx(4/5)+3/4-4/5)xx4/3]

Simplify : a. [(3^(3))xx3^(4)]-:3^(4) b. 18^(6)-:3^(12) c. [(5^(6))^(9)xx(5^(15))^(5)]-[(5^(13))^(5)xx(5^(4))^(16)] d. (3^(5)xx10^(5)xx25)-:(5^(7)xx6^(5)) e. ((2)/(b))^(18)xxb^(12)xx(3^(4))^(3) f. [(2^(4))^(2)xx2^(12)]-:4^(2) g. 12^(8)-:3^(6) h. [(7^(7))^(8)xx(7^(9))^(5)]-[(7^(11))^(6)xx(7^(7))^(5)] i. (25^(2)xxp^(4)xxq^(8))-:(5^(3)xxp^(4)xxq^(7)) j. ((a)/(3))^(24)xx2^(8)xx(3^(6))^(4)

{(81)^(-3/4)xx((16)^(1/4))/(6^(-2))xx(1/27)^(-4/3)}^(1/3)=