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Calculate the surface density of change...

Calculate the surface density of change at a place on the earth's surface where the rate of fall of potential is 250 volts per metre.
[Hint : rate of fall of potential =electric `=E=(sigma)/(epsilon_(0))` by Gauss's theorm.]

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The correct Answer is:
`2.21xx10^(-9) cm^(-2)`
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NN GHOSH-GAUSS THEOREM AND ITS APPLICATION-EXAMPLES(a)
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