A condenser is made of two thin plates with a glass slab of 2 mm thickness between them. The plates are `5 cmxx10 cm` and the relative premittivity of glass is `7.5 ` Find the capacitance of the capacitor.

A capacitor is composed of two plates separated by a sheet of insulating material 13 mm thick and or relative permittivity 4. The distance between the plates is increased to allow the insertion of second sheet 5 mm thick and of relative permittivity in_(r) . If the capacitance of the capacitor so formed is 1/3 of the original capacitance , find in_(r) .

A parallel plate condenser consists of two plates each of area 100cm^(2) . They are separated by mica sheet of thickness 8.85 mm. If the relative permittivity of mica is 6. Then capacity of parallel plate condenser is

A parallel plate capacitor has the space between its plates filled by two slabs of thickness (d)/(2) each and dielectric constant K_(1) and K_2 . d is the plate separation of the capacitor. The capacitance of the capacitor is

The time required to pass the light through a glass slab of 2 mm thick is (mu_("glass")=1.5)

A dielectric of thickness 5cm and dielectric constant 10 is introduced between the plates of a parallel plate capacitor having plate area 500 sq. cm and separation between the plates 10cm. The capacitance of the capacitor with dielectric slab is (epsi_(0) = 8.8 xx 10^(-12)C^(2)//N-m^(2))

A conducting slab of thickness ‘t’ is introduced between the plates of a parallel plate capacitor, separated by a distance d ( t lt d ) . Derive an expression for the capacitance of the capacitor. What will be its capacitance when t = d ?

A parallel plate capacitor is charged by connecting is plates to the terminals of a battery. The battery remains connected to the condenser plates and a glass plate is interposed between the plates of the capacitor, then

The two plates of a parallel plate capacitor are 4 mm apart. A slab of dielectric constant 3 and thickness 3 mm is introduced between the plates is so adujected that the capacitance of the capacitor becomes (2)/(3) rd of its original value. What is the new distance between the plates ?