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A slab of copper of thckness t is thrust...

A slab of copper of thckness t is thrust into a parallel plate capacitor of area A and plate separation d. What is the capacitance before and after the slab is introduced?
[Hint:There is no electric field inside a copper slab, or we may say that metals are isulators of `epsilon_(r)=infty]`

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The correct Answer is:
`(epsilon_(0)A)/(d),(epsilon_(0)A)/(d-1)`
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