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A capacitor with capacitance C = 400 pF ...

A capacitor with capacitance `C = 400 pF` is connected via a resistance `R = 650 Omega` to a source of voltage `V_(0)`. How soon will the voltage developed across the capacitor reach a value `V = 0.90 V_(0)` ?

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The correct Answer is:
`t=-RC ln(1-V/V_(o))=0.6mus`
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NN GHOSH-COMBINATION OF CAPACITORS-EXERCISE
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