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A capacitor filled with dielectric of pe...

A capacitor filled with dielectric of permittivity `epsilon = 2.1` losses half the charge acquired during a time interval `tau = 3.0 min`. Assuming the charge to leak only thorugh the dielectric filler, calculate its resistivity.

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The correct Answer is:
`p=(tau)/(epsi_(0)epsiln2)=1.4xx10^(13)Omegam`
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