When planet Jupiter is at a distance of ...

When planet Jupiter is at a distance of 824.7 million km from earth, its angular diameter is measured to be 35.72'' of arc. Calculate the diameter of Jupiter.

Topper's Solved these Questions

PHYSICAL WORLD AND MEASUREMENTS
SL ARORA|Exercise problem|10 Videos
PHYSICAL WORLD AND MEASUREMENTS
SL ARORA|Exercise problem for self practice|64 Videos
Physical world
SL ARORA|Exercise Exercise|49 Videos
PROJECTILE MOTION
SL ARORA|Exercise Problem For Self Practice|50 Videos

Similar Questions

Explore conceptually related problems

When the Jupiter is at a distance of 824.7 million km from the earth, its angular diameter is measured to be 35.72 sec of an arc. Calculate the diameter of jupiter.

when the planet Jupiter is at a distance of 824.7 million kilometers from the Earth, its angular diameter is mieaured to be 35.72'' of arc. Calculate the diameter of Jupiter ?

The distance of the sun from earth is 1.496xx10^(11)m. If the angular diameter of the sun is 2000'', find the diameter of the sun.

During a total solar eclipse, the disc of the moon almost completely covers the disc of the sun. If the distance of the Sun from the earth= 1.496xx10^(11) m, diameter of the Sun 1.393xx10^(8) m, then calculate the diameter of the moon.

The diameter of the moon is 3474km and is 384,400 km away from the earth. Calculate the angular diameter of the moon in arc minutes.

Planet A is at a distance of 9.35xx10^(6)km from Earth and planet B is 6.27xx10^(7) km from Earth. Which planet is nearer to Earth?

The moons distance from the earth is 360,000kms and its diameter subtends an angle of 31 at the eye of the observer.Find the diameter of the moon.

The diameter of the planet Jupiter is 3580km . What is its angular diameter when it is at a distance of 8.25xx10^(8)km from the earth?

The planet Jupiter is farther than Mars from Earth. Which planet seems to move faster when viewed from Earth? Explain.

SL ARORA-PHYSICAL WORLD AND MEASUREMENTS-Based on Combination

When planet Jupiter is at a distance of 824.7 million km from earth, i...
Text Solution
|
The length of two rods are recorded as l(1) = (25.2 pm 0.1) cm and l(2...
Text Solution
|
Two resistance (200 pm 4) Omega and (150 pm 3) Omega are connected in ...
Text Solution
|
The initial and final temperature of water were recorded as (56.3 pm 0...
Text Solution
|
If l(1) = (10.0 pm 0.1) cm and l(2) = (9.0 pm 0.1) cm , find the their...
Text Solution
|
A capacitor C = (2.0 +- 0.1)muF is charged to a voltage V = (20 +- 0.5...
Text Solution
|
The resistance R of a conductor is defind as the ratio of the potentia...
Text Solution
|
The relative density of a material is found by weighing the body first...
Text Solution
|
The length and breadth of a rectangular block are 25.2 cm and 16.8 cm,...
Text Solution
|
While measuring the volume of a sphere , an error of 1.2 % is commited...
Text Solution
|
The voltage across a lamp is (6.0 +- 0.1) V and the current passing th...
Text Solution
|
The radius of a sphere is measured to be (2.1+-0.5) cm. Calculate its ...
Text Solution
|
The radius of a sphere is (5.3 +- 0.1)cm The perecentage error in its ...
Text Solution
|
The measure of the diameter of a cylinder is (1.60 pm 0.01) cm and it...
Text Solution
|
The measured mass and volume of a body are 2.00 g and 5.0 cm^(3) respe...
Text Solution
|
Two resistance R(1) and R(2) are connected in (i) series and (ii) para...
Text Solution
|
A body travels uniformly a distance of ( 13.8 +- 0.2) m in a time (4.0...
Text Solution
|
The centripetal force acting on a body of mass m moving with speed v a...
Text Solution
|
The period of oscillation of a simple pendulum is T = 2 pi sqrt((L)/(g...
Text Solution
|
Calculate the percentage error in specific resistance , rho = pi r^(2)...
Text Solution
|
The Young's modulus Y is determined by stretching a wire by using the...
Text Solution
|